$\sin 120^{\circ} \cos 150^{\circ} - \cos 240^{\circ} \sin 330^{\circ}$ is equal to :

  • A
    $1$
  • B
    $-1$
  • C
    $\frac{2}{3}$
  • D
    $-\left(\frac{\sqrt{3}+1}{4}\right)$

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