lim _{x rightarrow 0} frac{(1-cos 2 x)}{x tan | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) આપેલ છે,$\lim _{x ightarrow 0} \frac{1-\cos 2 x}{x 	an 2 x+\frac{2 x}{3} 	an 3 x}$ નિત્યસમ $1-\cos 2x = 2 \sin^2 x$ નો ઉપયોગ કરતા: $= \lim _{x

Vedclass · Accepted Answer

$\frac{1}{2}$

Vedclass · Answer

(B) આપેલ છે,$\lim _{x ightarrow 0} \frac{1-\cos 2 x}{x 	an 2 x+\frac{2 x}{3} 	an 3 x}$ નિત્યસમ $1-\cos 2x = 2 \sin^2 x$ નો ઉપયોગ કરતા: $= \lim _{x ightarrow 0} \frac{2 \sin^2 x}{x 	an 2 x + \frac{2 x}{3} 	an 3 x}$ અંશ અને છેદને $x^2$ વડે ભાગતા: $= \lim _{x ightarrow 0} \frac{2 (\frac{\sin x}{x})^2}{\frac{	an 2 x}{x} + \frac{2}{3} \frac{	an 3 x}{x}}$ $= \lim _{x ightarrow 0} \frac{2 (\frac{\sin x}{x})^2}{2 (\frac{	an 2 x}{2 x}) + 2 (\frac{	an 3 x}{3 x})}$ $\lim _{x ightarrow 0} \frac{\sin x}{x} = 1$ અને $\lim _{x ightarrow 0} \frac{	an kx}{kx} = 1$ નો ઉપયોગ કરતા: $= \frac{2(1)^2}{2(1) + 2(1)} = \frac{2}{2+2} = \frac{2}{4} = \frac{1}{2}$

$\lim _{x \rightarrow 0} \frac{(1-\cos 2 x)}{x \tan 2 x+\frac{2 x}{3} \tan 3 x} = $

Similar Questions

$\mathop {\lim }\limits_{x \to 0} \frac{x}{{\tan x}}$ ની કિંમત શું થાય?

$\lim _{x \rightarrow 0} \frac{8}{\sin ^8 x} \left\{1-\cos \left(\frac{x^2}{2}\right)-\cos \left(\frac{x^2}{4}\right)+\cos \left(\frac{x^2}{2}\right) \cos \left(\frac{x^2}{4}\right)\right\} =$

$\lim _{x \rightarrow 0} \frac{\cos ax - \cos bx}{x^{2}}$ ની કિંમત શોધો.

$\lim _{x \rightarrow 0} \frac{\sin ^{2}\left(\pi \cos ^{4} x\right)}{x^{4}}$ ની કિંમત શોધો.

$\mathop {\lim }\limits_{\theta \to 0} \frac{{\sin 3\theta - \sin \theta }}{{\sin \theta }} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module