A toroid has a core (non-ferromagnetic) of in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given:Inner radius $r_1 = 24 \ cm = 0.24 \ m$Outer radius $r_2 = 26 \ cm = 0.26 \ m$Number of turns $N = 2000$Current $I = 12 \ A$The mean radius

Vedclass · Accepted Answer

$1.92 	imes 10^{-2} \ T$

Vedclass · Answer

(A) Given:Inner radius $r_1 = 24 \ cm = 0.24 \ m$Outer radius $r_2 = 26 \ cm = 0.26 \ m$Number of turns $N = 2000$Current $I = 12 \ A$The mean radius $r$ of the toroid is given by:$r = \frac{r_1 + r_2}{2} = \frac{24 + 26}{2} = 25 \ cm = 0.25 \ m$The magnetic field $B$ inside the core of a toroid is given by the formula:$B = \mu_0 n I$where $n$ is the number of turns per unit length, $n = \frac{N}{2 \pi r}$.Substituting the values:$B = \mu_0 \left( \frac{N}{2 \pi r} ight) I$$B = (4 \pi 	imes 10^{-7}) 	imes \left( \frac{2000}{2 \pi 	imes 0.25} ight) 	imes 12$$B = (2 	imes 10^{-7}) 	imes \left( \frac{2000}{0.25} ight) 	imes 12$$B = (2 	imes 10^{-7}) 	imes 8000 	imes 12$$B = 192000 	imes 10^{-7} \ T$$B = 1.92 	imes 10^{-2} \ T$

$A$ toroid has a core (non-ferromagnetic) of inner radius $24 \ cm$ and outer radius $26 \ cm$ around which $2000$ turns of a wire are wound. If the current in the wire is $12 \ A$, the magnetic field inside the core of the toroid is:

Similar Questions

$A$ long solenoid has $200$ turns per cm and carries a current of $2.5 \, A$. The magnetic field at its centre is (given $\mu_0 = 4\pi \times 10^{-7} \, T \cdot m/A$):

What are electromagnets?

$A$ long solenoid is formed by winding $20$ $turns/cm$. The current necessary to produce a magnetic field of $20$ $mT$ inside the solenoid will be approximately ..... $A$ $(\frac{\mu_0}{4\pi} = 10^{-7} \text{ T m/A})$.

To manufacture a solenoid of length $\ell$ and inductance $L$,the length of the thin wire required is (Diameter of the solenoid is very small compared to its length,$\mu_0$ is the permeability of free space).

If the magnetic field inside a solenoid is $B$,then the magnetic energy stored in it per unit volume is (where $c$ is the speed of light in vacuum and $\varepsilon_0$ is the permittivity of free space).

Vedclass Test Series

Exam Paper Generator

Online Exam Module