A particle of charge q and mass m moves in a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic moment $M$ of a particle of charge $q$ moving in a circular orbit of radius $r$ with speed $v$ is given by $M = I A = (\frac{q}{T}) (

Vedclass · Accepted Answer

$\frac{q}{2 m}$

Vedclass · Answer

(C) The magnetic moment $M$ of a particle of charge $q$ moving in a circular orbit of radius $r$ with speed $v$ is given by $M = I A = (\frac{q}{T}) (\pi r^2) = (\frac{q \omega}{2 \pi}) (\pi r^2) = \frac{1}{2} q \omega r^2$.The angular momentum $L$ of the particle is given by $L = mvr = m(\omega r)r = m \omega r^2$.The ratio of the magnitude of magnetic moment to angular momentum is $\frac{M}{L} = \frac{\frac{1}{2} q \omega r^2}{m \omega r^2} = \frac{q}{2m}$.This ratio is known as the gyromagnetic ratio.

$A$ particle of charge $q$ and mass $m$ moves in a circular orbit of radius $r$ with angular speed $\omega$. The ratio of the magnitude of its magnetic moment to that of its angular momentum is

Similar Questions

Obtain an expression for the orbital magnetic moment of an electron rotating about the nucleus in an atom and explain the gyromagnetic ratio.

$A$ particle of charge '$q$' and mass '$m$' moves in a circular orbit of radius '$r$' with angular speed '$\omega$'. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

If the charge to mass ratio of an electron is $A \ C/kg$,then the gyromagnetic ratio of an orbital electron in $C/kg$ is

The ratio of the magnetic dipole moment to the angular momentum of the electron in the $1^{st}$ orbit of a hydrogen atom is

What is the gyromagnetic ratio? Give its magnitude.

Vedclass Test Series

Exam Paper Generator

Online Exam Module