$A$ bag contains $3$ red, $5$ black and $7$ blue balls. If three balls are drawn at random simultaneously from the bag, then the probability of getting at least two blue balls is

  • A
    $\frac{29}{65}$
  • B
    $\frac{29}{130}$
  • C
    $\frac{9}{65}$
  • D
    $\frac{9}{130}$

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