A bag contains 9 identical black balls number | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Total number of balls $= 9 + 4 = 13$. Total ways to draw $3$ balls from $13$ is $^{13}C_3 = \frac{13 	imes 12 	imes 11}{3 	imes 2 	imes 1} = 2

Vedclass · Accepted Answer

$\frac{101}{143}$

Vedclass · Answer

(A) Total number of balls $= 9 + 4 = 13$. Total ways to draw $3$ balls from $13$ is $^{13}C_3 = \frac{13 	imes 12 	imes 11}{3 	imes 2 	imes 1} = 286$. The probability of getting at least one white ball is $1 - P(	ext{no white ball})$. If no white ball is drawn, all $3$ balls must be black. Number of ways to draw $3$ black balls $= ^9C_3 = \frac{9 	imes 8 	imes 7}{3 	imes 2 	imes 1} = 84$. $P(	ext{no white ball}) = \frac{84}{286} = \frac{42}{143}$. $P(	ext{at least one white ball}) = 1 - \frac{42}{143} = \frac{101}{143}$. Therefore, option $A$ is correct.

$A$ bag contains $9$ identical black balls numbered $1$ to $9$ and $4$ identical white balls numbered $1$ to $4$. If $3$ balls are drawn at a time randomly from that bag, then the probability of getting at least one white ball is

Similar Questions

$A$ deck consists of $4$ Aces,$4$ Kings,$4$ Queens,and $4$ Jacks. If $2$ cards are drawn at random from this deck of $16$ cards,what is the probability that at least one card is an Ace?

Out of $13$ applicants for a job,$5$ are women and $8$ are men. Two persons are to be selected for the job. What is the probability that at least one woman is selected?

$A$ seven-digit number is formed using the digits $3, 3, 4, 4, 4, 5, 5$. The probability that the number so formed is divisible by $2$ is ..... .

$A$ basket contains $3$ mangoes and $3$ apples. If two fruits are selected at random,what is the probability of getting one mango and one apple?

Three numbers are chosen from $1$ to $30$. The probability that the minimum number is $10$ and the maximum number is $26$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module