$A, B$ are the events in a random experiment. If $P(A)=\frac{1}{2}, P(B)=\frac{1}{3}, P(A \cap B)=\frac{1}{4}$, then $P\left(\frac{A^{c}}{B^{c}}\right)+P\left(\frac{A}{B}\right)=$

  • A
    $1$
  • B
    $\frac{4}{5}$
  • C
    $\frac{11}{8}$
  • D
    $\frac{7}{3}$

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