A person moves 30 ,m North and then 20 ,m tow | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the origin be $O(0,0)$.$1$. The person moves $30 \,m$ North: Position becomes $(0, 30)$.$2$. Then moves $20 \,m$ East: Position becomes $(20,

Vedclass · Accepted Answer

$10 \,m$ along West

Vedclass · Answer

(C) Let the origin be $O(0,0)$.$1$. The person moves $30 \,m$ North: Position becomes $(0, 30)$.$2$. Then moves $20 \,m$ East: Position becomes $(20, 30)$.$3$. Finally moves $30 \sqrt{2} \,m$ in South-West direction. South-West direction makes an angle of $45^{\circ}$ with the South and West axes. The components of this displacement are:$\Delta x = -30 \sqrt{2} \cos(45^{\circ}) = -30 \sqrt{2} 	imes \frac{1}{\sqrt{2}} = -30 \,m$$\Delta y = -30 \sqrt{2} \sin(45^{\circ}) = -30 \sqrt{2} 	imes \frac{1}{\sqrt{2}} = -30 \,m$New position = $(20 - 30, 30 - 30) = (-10, 0)$.The displacement from the origin $(0, 0)$ to $(-10, 0)$ is $10 \,m$ along the West direction.

$A$ person moves $30 \,m$ North and then $20 \,m$ towards East and finally $30 \sqrt{2} \,m$ in South-West direction. The displacement of the person from the origin will be

Similar Questions

If two forces of equal magnitudes act simultaneously on a body in the east and the north directions,then:

Two forces $P + Q$ and $P - Q$ make an angle $2 \alpha$ with each other,and their resultant makes an angle $\theta$ with the bisector of the angle between them. Then:

The magnitudes of pairs of displacement vectors are given. Which pair of displacement vectors cannot be added to give a resultant vector of magnitude $13 \, cm$?

$A$ car travels a distance of $6 \, km$ at an angle of $45^\circ$ with the East,and then travels a distance of $4 \, km$ at an angle of $135^\circ$ with the East. What is the distance from the origin?

What is the meaning of subtraction of two vectors?

Vedclass Test Series

Exam Paper Generator

Online Exam Module