SiCl_4 on hydrolysis forms 'X' and HCl. Compo | vedclass

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(D) The hydrolysis of silicon tetrachloride $(SiCl_4)$ proceeds as follows:$SiCl_4 + 4H_2O \longrightarrow H_4SiO_4 + 4HCl$Here,'$X$' is silicic acid

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$H_4SiO_4, SiO_2$

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(D) The hydrolysis of silicon tetrachloride $(SiCl_4)$ proceeds as follows:$SiCl_4 + 4H_2O \longrightarrow H_4SiO_4 + 4HCl$Here,'$X$' is silicic acid $(H_4SiO_4)$.Upon heating at $1000^{\circ} C$, silicic acid undergoes dehydration:$H_4SiO_4 \xrightarrow{\Delta, 1000^{\circ} C} SiO_2 + 2H_2O$Here,'$Y$' is silicon dioxide $(SiO_2)$.Therefore,'$X$' is $H_4SiO_4$ and '$Y$' is $SiO_2$.

$SiCl_4$ on hydrolysis forms '$X$' and $HCl$. Compound '$X$' loses water at $1000^{\circ} C$ and gives '$Y$'. Compounds '$X$' and '$Y$' respectively are:

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