XeF_6 on partial hydrolysis gives 'X' and HF. | vedclass

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Question

(C) The partial hydrolysis of $XeF_6$ is represented by the following chemical equation:$XeF_6 + H_2O \rightarrow XeOF_4 + 2HF$Here,'$X$' is $XeOF_4$.

Vedclass · Accepted Answer

Square pyramidal

Vedclass · Answer

(C) The partial hydrolysis of $XeF_6$ is represented by the following chemical equation:$XeF_6 + H_2O \rightarrow XeOF_4 + 2HF$Here,'$X$' is $XeOF_4$.The central atom $Xe$ in $XeOF_4$ has $8$ valence electrons. It forms $4$ single bonds with $F$ atoms and $1$ double bond with the $O$ atom.Total electron pairs around $Xe = 5$ (bonding pairs) + $1$ (lone pair) = $6$ electron pairs.This corresponds to $sp^3d^2$ hybridization with an octahedral electron geometry.Due to the presence of one lone pair, the shape of $XeOF_4$ is square pyramidal.

$XeF_6$ on partial hydrolysis gives '$X$' and $HF$. The shape of '$X$' is

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