$A$ compound microscope has an objective of focal length $1.25 \ cm$ and an eyepiece of focal length $5 \ cm$ separated by a distance of $7.5 \ cm$. The total magnification produced by the microscope when the final image forms at infinity is

The focal length of the objective and eye lenses of a microscope are $1.6 \, cm$ and $2.5 \, cm$ respectively. The distance between the two lenses is $21.7 \, cm$. If the final image is formed at infinity,what is the linear magnification?

In a Ramsden eyepiece,two planoconvex lenses,each of focal length $f$,are separated by a distance of $12 \ cm$. The equivalent focal length (in $cm$) of the eyepiece is:

Which of the following statements are true in the context of a Compound Microscope?
$(A)$ The objective lens forms a virtual and magnified image.
$(B)$ The objective lens has a very short focal length.
$(C)$ The eyepiece acts as a simple magnifying glass.
$(D)$ The eyepiece is a concave lens.

In a simple microscope,if the final image is located at infinity,then its magnifying power is:

In a compound microscope,the focal lengths of the objective and eye lens are $2.5 \, cm$ and $5 \, cm$ respectively. An object is placed at $3.75 \, cm$ in front of the objective. If the final image is formed at the least distance of distinct vision,then the distance between the two lenses (length of the microscope tube) is.......$cm$.