$KO_2$ exhibits paramagnetic behaviour. This is due to the paramagnetic nature of

  • A
    $KO^{-}$
  • B
    $K^{+}$
  • C
    $O_2$
  • D
    $O_2^{-}$

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Similar Questions

Consider the following changes $I$ and $II$ as shown in the figure. The correct statements about these changes $(I)$ and $(II)$ in accordance with $MO$ theory are:
$A$) In $(I)$ bond order increases by $0.5$ from the existing value.
$B$) In $(II)$ bond order decreases by $0.5$ from the existing value.
$C$) In both $(I)$ and $(II)$ magnetic property is changed.
$D$) In both $(I)$ and $(II)$ magnetic property is not changed.

In $O_2^-$,$O_2$,and $O_2^{2-}$ molecular species,the total number of antibonding electrons respectively are

Match List-$I$ with List-$II$.
List-$I$ List-$II$
$A$. $\Psi_{MO} = \Psi_{A} - \Psi_{B}$ $I$. Dipole moment
$B$. $\mu = Q \times r$ $II$. Bonding molecular orbital
$C$. $\frac{N_{b} - N_{a}}{2}$ $III$. Anti-bonding molecular orbital
$D$. $\Psi_{MO} = \Psi_{A} + \Psi_{B}$ $IV$. Bond order

Which among the following molecules exhibits paramagnetism?

The correct molecular orbital diagram for $F_2$ molecule in the ground state is

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