$A$ transistor having a $\beta$ equal to $80$ has a change in base current of $250 \mu A$. What is the change in collector current?

The collector supply voltage is $6 \text{ V}$ and a voltage drop across a resistor of $600 \Omega$ in the collector circuit is $0.6 \text{ V}$,in a circuit of a transistor connected in common emitter mode. If the current gain is $20$,then the base current is: (in $\text{ mA}$)

For a transistor amplifier in common emitter configuration with a load impedance of $1 \ k\Omega$ ($h_{fe} = 50$ and $h_{oe} = 25 \ \mu A/V$),the current gain is:

In an $NPN$ transistor circuit,the collector current is $10 \,mA$. If $90\%$ of the electrons emitted reach the collector,the emitter current $(i_E)$ and base current $(i_B)$ are given by

In a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2 \, k\Omega$ is $2 \, V$. If the base resistance is $1 \, k\Omega$ and the current amplification of the transistor is $100$,the input signal voltage is

If the resistance $R_1$ is increased (see figure), how will the readings of the ammeter and voltmeter change?