0.1 mol of NaCl is dissolved in 100 g of wa | vedclass

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(B) The number of moles of $NaCl$ is $n_{NaCl} = 0.1 \ mol$. The mass of water is $100 \ g$. The molar mass of water $(H_2O)$ is $18 \ g/mol$. The num

Vedclass · Accepted Answer

$0.0177$

Vedclass · Answer

(B) The number of moles of $NaCl$ is $n_{NaCl} = 0.1 \ mol$. The mass of water is $100 \ g$. The molar mass of water $(H_2O)$ is $18 \ g/mol$. The number of moles of water is $n_{H_2O} = \frac{100 \ g}{18 \ g/mol} \approx 5.556 \ mol$. The mole fraction of $NaCl$ $(X_{NaCl})$ is given by the formula: $X_{NaCl} = \frac{n_{NaCl}}{n_{NaCl} + n_{H_2O}} = \frac{0.1}{0.1 + 5.556} = \frac{0.1}{5.656} \approx 0.0177$.

$0.1 \ mol$ of $NaCl$ is dissolved in $100 \ g$ of water. The mole fraction of $NaCl$ is

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