$x \ g$ of urea (molar mass $60 \ g \ mol^{-1}$) is completely dissolved in $y \ g$ of pure water and the solution boiled at $373.202 \ K$. If the boiling point of pure water at $1.013 \ bar$ is $373.15 \ K$, then $x:y$ is $(K_b(H_2O) = 0.52 \ K \ kg \ mol^{-1})$
- A$6.0 \times 10^{-3}$
- B$3.0 \times 10^{-3}$
- C$9.0 \times 10^{-3}$
- D$4.5 \times 10^{-3}$
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