$15 \%$ aqueous solution of glucose (molecular weight $= 180 \ g/mol$) is isotonic with $8 \%$ aqueous solution containing an unknown non-dissociable solute. What is the molecular weight of the unknown solute?

Consider the following pairs of solutions which will be isotonic at the same temperature. The number of pairs of solutions that are isotonic is/are..........
$A.$ $1 \ M$ aq. $NaCl$ and $2 \ M$ aq. Urea
$B.$ $1 \ M$ aq. $CaCl_2$ and $1.5 \ M$ aq. $KCl$
$C.$ $1.5 \ M$ aq. $AlCl_3$ and $2 \ M$ aq. $Na_2SO_4$
$D.$ $2.5 \ M$ aq. $KCl$ and $1 \ M$ aq. $Al_2(SO_4)_3$

$A$ solution is made by dissolving $20 \ g$ of a substance in $500 \ mL$ of water. Its osmotic pressure was found to be $600 \ mm$ of $Hg$ at $15 \ ^oC$. The molecular weight of the substance is

$XY$ is the membrane $/$ partition between two chambers $1$ and $2$ containing sugar solutions of concentration $c_1$ and $c_2$ $(c_1 > c_2)$ $mol \ L^{-1}$. For the reverse osmosis to take place,identify the correct condition (Here $p_1$ and $p_2$ are pressures applied on chamber $1$ and $2$):
$(A)$ Membrane $/$ Partition $:$ Cellophane,$p_1 > \pi$
$(B)$ Membrane $/$ Partition $:$ Porous,$p_2 > \pi$
$(C)$ Membrane $/$ Partition $:$ Parchment paper,$p_1 > \pi$
$(D)$ Membrane $/$ Partition $:$ Cellophane,$p_2 > \pi$
Choose the correct answer from the options given below $:$

The solution in which the blood cells retain their normal form is with regard to the blood:

The osmotic pressure of a $5\% \ (w/V)$ solution of cane sugar at $150\,^{\circ}C$ will be $.......$ $atm$.