x grams of calcium carbonate was completely b | vedclass

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(D) The thermal decomposition of calcium carbonate is given by the reaction:
$CaCO_{3(s)} \xrightarrow{\Delta} CaO_{(s)} + CO_2(g)$
From the stoichi

Vedclass · Accepted Answer

$50$

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(D) The thermal decomposition of calcium carbonate is given by the reaction:
$CaCO_{3(s)} \xrightarrow{\Delta} CaO_{(s)} + CO_2(g)$
From the stoichiometry of the reaction:
$1 	ext{ mole of } CaCO_3 (100 	ext{ g}) 	ext{ produces } 1 	ext{ mole of } CaO (56 	ext{ g})$.
Since $56 	ext{ g}$ of $CaO$ is obtained from $100 	ext{ g}$ of $CaCO_3$,
$28 	ext{ g}$ of $CaO$ is obtained from:
$x = \frac{100 	imes 28}{56} = 50 	ext{ g}$.
Therefore, the value of $x$ is $50$.

$x$ grams of calcium carbonate was completely burnt in air. The weight of the solid residue formed is $28 \,g$. What is the value of $x$ (in grams)?

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