A monoatomic gas does 100 J of work when it i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For an isobaric process, the work done is given by $W = P \Delta V = n R \Delta T = 100 J$.For a monoatomic gas, the molar heat capacity at consta

Vedclass · Accepted Answer

$250$

Vedclass · Answer

(C) For an isobaric process, the work done is given by $W = P \Delta V = n R \Delta T = 100 J$.For a monoatomic gas, the molar heat capacity at constant pressure is $C_P = \frac{5}{2} R$.The heat supplied to the gas is given by $Q = n C_P \Delta T$.Substituting the value of $C_P$, we get $Q = n (\frac{5}{2} R) \Delta T = \frac{5}{2} (n R \Delta T)$.Since $n R \Delta T = 100 J$, we have $Q = \frac{5}{2} 	imes 100 J = 250 J$.

$A$ monoatomic gas does $100 J$ of work when it is expanded isobarically. How much heat is given to the gas in the process (in $J$)?

Similar Questions

The thermodynamic process in which no work is done by the gas or on the gas is

Define an isobaric process. Derive an expression for the work done in such a process.

$A$ sample of gas expands from volume ${V_1}$ to ${V_2}$. The amount of work done by the gas is greatest when the expansion is

$A$ gas expands by $0.25 \, m^3$ at a constant pressure of $10^3 \, N/m^2$. The work done is:

The change in the internal energy of $3$ moles of a gas heated at constant volume from $20^{\circ}C$ to $40^{\circ}C$ is $1080 \ J$. The molar specific heat of the gas at constant volume in $J \ mol^{-1} \ K^{-1}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module