A solid of 2 ,kg mass absorbs 50 ,kJ when its | vedclass

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(A) The heat absorbed by a solid is given by the formula: $\Delta Q = m s \Delta T$, where $s$ is the specific heat capacity of the solid.Given values

Vedclass · Accepted Answer

$500$

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(A) The heat absorbed by a solid is given by the formula: $\Delta Q = m s \Delta T$, where $s$ is the specific heat capacity of the solid.Given values are: mass $m = 2 \,kg$, heat absorbed $\Delta Q = 50 \,kJ = 50,000 \,J$, and change in temperature $\Delta T = 70^{\circ} C - 20^{\circ} C = 50^{\circ} C$.Rearranging the formula to solve for $s$: $s = \frac{\Delta Q}{m \cdot \Delta T}$.Substituting the values: $s = \frac{50,000 \,J}{2 \,kg 	imes 50^{\circ} C} = \frac{50,000}{100} \,J / kg^{\circ} C = 500 \,J / kg^{\circ} C$.Therefore, the specific heat capacity of the solid is $500 \,J / kg^{\circ} C$.

$A$ solid of $2 \,kg$ mass absorbs $50 \,kJ$ when its temperature is raised from $20^{\circ} C$ to $70^{\circ} C$. The specific heat capacity of this solid in units of $J / kg^{\circ} C$ is

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