$A$ $5 \mu F$ capacitor is connected in series with a $10 \mu F$ capacitor. When a $300 \ V$ potential difference is applied across this combination, the total energy stored in the capacitors is (in $J$)

  • A
    $18$
  • B
    $1.5$
  • C
    $0.15$
  • D
    $0.10$

Explore More

Similar Questions

What is the effective capacitance between points $X$ and $Y$ in $\mu F$?

In the adjoining figure, the potential difference between $X$ and $Y$ is $60 \ V$. The potential difference between the points $M$ and $N$ will be: (in $V$)

The total capacity of the system of capacitors shown in the adjoining figure between the points $A$ and $B$ is $..... \ \mu F$.

Difficult
View Solution

Three parallel plate air capacitors are connected in parallel. Each capacitor has plate area $\frac{A}{3}$ and the separation between the plates is $d, 2d$ and $3d$ respectively. The equivalent capacity of the combination is ($\varepsilon_0 =$ absolute permittivity of free space).

Five capacitors,each of capacity $C$,are connected as shown in the figure. The resultant capacity between $A$ and $B$ is $14 \mu F$. The capacity of each capacitor is (in $\mu F$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo