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(B) The intensity $I$ of light from a point source follows the inverse square law, $I \propto \frac{1}{d^2}$, where $d$ is the distance from the sourc

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Photoelectric current will decrease

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(B) The intensity $I$ of light from a point source follows the inverse square law, $I \propto \frac{1}{d^2}$, where $d$ is the distance from the source.When the distance $d$ is doubled, the intensity $I$ becomes $\frac{1}{4}$ of its original value.The photoelectric current is directly proportional to the intensity of incident light.Since the intensity decreases, the number of photons hitting the surface per unit time decreases, resulting in a decrease in the photoelectric current.Stopping potential and maximum kinetic energy depend on the frequency of the incident light, not on its intensity.Therefore, the correct result is that the photoelectric current will decrease.

$A$ point source of light is used in an experiment of photoelectric effect. If the distance between the source and the photoelectric surface is doubled, which of the following may result?

Similar Questions

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