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(D) According to Gauss's Law, the total electric flux through a closed surface is $\phi_{total} = q / \varepsilon_{0}$.When a charge $q$ is placed at

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$q / 24 \varepsilon_{0}$

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(D) According to Gauss's Law, the total electric flux through a closed surface is $\phi_{total} = q / \varepsilon_{0}$.When a charge $q$ is placed at one corner of a cube, the cube can be considered as part of a larger Gaussian surface consisting of $8$ identical cubes to enclose the charge completely at the center.Thus, the total flux through the entire cube is $\phi_{cube} = q / (8 \varepsilon_{0})$.The charge $q$ lies on three faces of the cube. The electric field lines are parallel to these three faces, so the electric flux through these three faces is zero.The remaining flux $\phi_{cube}$ is distributed equally among the other three faces of the cube.Therefore, the flux through any one of the other three faces is $\phi = \frac{1}{3} 	imes \phi_{cube} = \frac{1}{3} 	imes \frac{q}{8 \varepsilon_{0}} = \frac{q}{24 \varepsilon_{0}}$.

$A$ charge $q$ is placed at one corner of a cube. The electric flux through any of the three faces adjacent to the charge is zero. The flux through any one of the other three faces is

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