A hollow metal sphere of radius R is charged | vedclass

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Question

(B) Inside a hollow charged metal sphere, the electric field intensity is always zero because there is no charge enclosed within the Gaussian surface

Vedclass · Accepted Answer

$\frac{Q}{4 \pi \varepsilon_{0} R}$ and zero

Vedclass · Answer

(B) Inside a hollow charged metal sphere, the electric field intensity is always zero because there is no charge enclosed within the Gaussian surface inside the sphere.$	herefore E = 0$.However, the electric potential inside the sphere is constant and equal to the potential at its surface.The potential on the surface of the hollow sphere is given by:$V = \frac{1}{4 \pi \varepsilon_{0}} \cdot \frac{Q}{R} = \frac{Q}{4 \pi \varepsilon_{0} R}$.Thus, inside the sphere, the potential is $\frac{Q}{4 \pi \varepsilon_{0} R}$ and the electric field intensity is zero.

$A$ hollow metal sphere of radius $R$ is charged with a charge $Q$. The electric potential and intensity inside the sphere are respectively

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