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(C) The reaction is $C_3H_8 \xrightarrow{-2H, +2Cl} C_3H_6Cl_2$. The structural isomers of $C_3H_6Cl_2$ are: $1,1$-dichloropropane $2,2$-dichloropropa

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$5$

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(C) The reaction is $C_3H_8 \xrightarrow{-2H, +2Cl} C_3H_6Cl_2$. The structural isomers of $C_3H_6Cl_2$ are: $1,1$-dichloropropane $2,2$-dichloropropane $1,2$-dichloropropane $1,3$-dichloropropane Among these, $1,2$-dichloropropane contains a chiral carbon atom (the $C-2$ atom), which means it exists as a pair of enantiomers (optical isomers). Therefore, the total number of isomers is $4$ structural isomers + $1$ additional enantiomer = $5$ isomers.

$A$ compound is formed by the substitution of two hydrogen atoms with two chlorine atoms in propane. The number of possible isomeric compounds is

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