$A$ proton of mass $m$ moving with a speed $v$ ($v << c$, where $c$ is the velocity of light in vacuum) completes a circular orbit in time $T$ in a uniform magnetic field. If the speed of the proton is increased to $\sqrt{2}v$, what will be the time needed to complete the circular orbit?
- A$\sqrt{T}$
- B$T$
- C$\frac{T}{\sqrt{2}}$
- D$\frac{T}{2}$
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