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(B) For a bob of mass $m$ moving in a vertical circular path of radius $L$ with speed $v$, the forces acting on the bob along the radial direction are

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$m g \cos 	heta + m v^{2} / L$

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(B) For a bob of mass $m$ moving in a vertical circular path of radius $L$ with speed $v$, the forces acting on the bob along the radial direction are the tension $T$ (towards the center) and the component of weight $mg \cos 	heta$ (away from the center).The net centripetal force required for circular motion is provided by the resultant of these radial forces:$T - mg \cos 	heta = \frac{mv^2}{L}$Rearranging the equation to solve for the tension $T$:$T = \frac{mv^2}{L} + mg \cos 	heta$

$A$ simple pendulum of length $L$ swings in a vertical plane. The tension in the string when it makes an angle $\theta$ with the vertical and the bob of mass $m$ moves with a speed $v$ is (where $g$ is the gravitational acceleration):

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