1 mL of water has 25 drops. Let N_0 be the A | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Volume of one drop $= (\frac{1}{25}) \ mL$$	herefore$ Mass of $1$ drop $= V 	imes d = (\frac{1}{25} \ mL)(1 \ g / mL) = \frac{1}{25} \ g$Number

Vedclass · Accepted Answer

$\frac{0.02}{9} \ N_0$

Vedclass · Answer

(A) Volume of one drop $= (\frac{1}{25}) \ mL$$	herefore$ Mass of $1$ drop $= V 	imes d = (\frac{1}{25} \ mL)(1 \ g / mL) = \frac{1}{25} \ g$Number of moles of $H_2O = \frac{	ext{Mass of water in one drop}}{	ext{Molar mass of water}} = \frac{1/25}{18} = \frac{1}{450} \ mol$$	herefore$ Number of $H_2O$ molecules $= \frac{1}{450} \ N_0 = \frac{0.02}{9} \ N_0$

$1 \ mL$ of water has $25$ drops. Let $N_0$ be the Avogadro number. What is the number of molecules present in $1$ drop of water? (Density of water $= 1 \ g / mL$)

Similar Questions

Avogadro number is

What is the mass of $1$ mole of electrons?

How many oxygen atoms are present in $4.4 \ g$ of $CO_2$?

If $10^{21}$ molecules are removed from $200 \, mg$ of $CO_2$,then the number of moles of $CO_2$ left is .....

The number of moles of $SO_2Cl_2$ in $13.5 \ g$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module