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Question

(A) For a long cylindrical conductor of radius $R$ carrying a current $I$ distributed uniformly, the magnetic field $B$ at a distance $r$ from the axi

Vedclass · Accepted Answer

$A$. maximum at either ends of the conductor and minimum at the midpoint

Vedclass · Answer

(A) For a long cylindrical conductor of radius $R$ carrying a current $I$ distributed uniformly, the magnetic field $B$ at a distance $r$ from the axis is given by Ampere's circuital law:$1$. Inside the conductor $(r $2$. At the surface $(r = R)$: $B = \frac{\mu_0 I}{2 \pi R}$, which is the maximum value.$3$. Outside the conductor $(r > R)$: $B = \frac{\mu_0 I}{2 \pi r}$, which decreases as $r$ increases.Thus, the magnetic field is minimum at the axis of the conductor (statement $D$). Statement $A, B, C, E$ are incorrect. Therefore, only statement $D$ is correct.

$A$ long cylindrical conductor with a large cross-section carries an electric current distributed uniformly over its cross-section. The magnetic field due to this current is:

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