A plane electromagnetic wave is moving in fre | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The direction of propagation of the wave is given by the wave vector $\vec{k}$, which is along the $z$-axis ($+\hat{k}$ direction). The relationsh

Vedclass · Accepted Answer

$-1.8 	imes 10^{-7} \sin(kz - \omega t) \hat{i} \ T$

Vedclass · Answer

(A) The direction of propagation of the wave is given by the wave vector $\vec{k}$, which is along the $z$-axis ($+\hat{k}$ direction). The relationship between the electric field $\vec{E}$, magnetic field $\vec{B}$, and the direction of propagation $\hat{c}$ is given by $\vec{B} = \frac{1}{c} (\hat{c} 	imes \vec{E})$. Here, $\hat{c} = \hat{k}$ and $\vec{E} = E_0 \sin(kz - \omega t) \hat{j}$. The direction of $\vec{B}$ is $\hat{k} 	imes \hat{j} = -\hat{i}$. The magnitude of the magnetic field is $B_0 = \frac{E_0}{c} = \frac{54}{3 	imes 10^8} = 18 	imes 10^{-8} = 1.8 	imes 10^{-7} \ T$. Therefore, $\vec{B} = -1.8 	imes 10^{-7} \sin(kz - \omega t) \hat{i} \ T$.

$A$ plane electromagnetic wave is moving in free space with velocity $c = 3 \times 10^8 \ m/s$ and its electric field is given as $\vec{E} = 54 \sin(kz - \omega t) \hat{j} \ V/m$, where $\hat{j}$ is the unit vector along the $y$-axis. The magnetic field vector $\vec{B}$ of the wave is:

Similar Questions

For electromagnetic waves,the phase difference between the $\vec{E}$ and $\vec{B}$ vectors (for the region far from the source) is......

The rms value of the electric field of an electromagnetic wave emitted by a source is $660 \ NC^{-1}$. The average energy density of the electromagnetic wave is

How are microwaves produced?

If the peak value of the magnetic field of an electromagnetic wave is $30 \times 10^{-9} \ T$,then the peak value of the electric field is (in $Vm^{-1}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module