A 15.0 mutext{F} capacitor is connected to a | vedclass

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(B) The capacitive reactance $X_C$ is given by the formula $X_C = \frac{1}{2\pi f C}$.Given values are frequency $f = 50 	ext{ Hz}$ and capacitance $

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$212$

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(B) The capacitive reactance $X_C$ is given by the formula $X_C = \frac{1}{2\pi f C}$.Given values are frequency $f = 50 	ext{ Hz}$ and capacitance $C = 15.0 \mu	ext{F} = 15.0 	imes 10^{-6} 	ext{ F}$.Substituting these values into the formula:$X_C = \frac{1}{2 	imes 3.14159 	imes 50 	imes 15.0 	imes 10^{-6}}$$X_C = \frac{1}{314.159 	imes 15.0 	imes 10^{-6}}$$X_C = \frac{1}{4712.385 	imes 10^{-6}}$$X_C = \frac{10^6}{4712.385} \approx 212.2 \Omega$.Rounding to the nearest integer, the capacitive reactance is $212 \Omega$.

$A$ $15.0 \mu\text{F}$ capacitor is connected to a $220 \text{ V}$, $50 \text{ Hz}$ source. The capacitive reactance of the circuit is . . . . . . $\Omega$.

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