text{CH}_3text{COOH} xrightarrow{text{LiAlH}_ | vedclass

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(C) The reaction proceeds as follows:$1$) Reduction of $	ext{CH}_3	ext{COOH}$ by $	ext{LiAlH}_4$ gives $	ext{CH}_3	ext{CH}_2	ext{OH}$ (Ethanol),

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Ethene

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(C) The reaction proceeds as follows:$1$) Reduction of $	ext{CH}_3	ext{COOH}$ by $	ext{LiAlH}_4$ gives $	ext{CH}_3	ext{CH}_2	ext{OH}$ (Ethanol), which is product $	ext{X}$.$2$) Reaction of $	ext{CH}_3	ext{CH}_2	ext{OH}$ with $	ext{PCl}_5$ gives $	ext{CH}_3	ext{CH}_2	ext{Cl}$ (Ethyl chloride), which is product $	ext{Y}$.$3$) Dehydrohalogenation (elimination reaction) of $	ext{CH}_3	ext{CH}_2	ext{Cl}$ with alcoholic $	ext{KOH}$ gives $	ext{CH}_2=	ext{CH}_2$ (Ethene), which is product $	ext{Z}$.

$\text{CH}_3\text{COOH} \xrightarrow{\text{LiAlH}_4} \text{X} \xrightarrow{\text{PCl}_5} \text{Y} \xrightarrow{\text{Alcoholic KOH}} \text{Z}$. Find product '$Z$' in the above reaction.

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