Difficult
$RMgI$ when treated with ice-cold water liberated a gas which occupied $1.4 \text{ dm}^3/\text{g}$ at $STP$. The gas produced is further reacted with iodine in the presence of $HIO_3$ to give compound $(X)$. Compound $(X)$ in the presence of $Na$ and dry ether produced compound $(Y)$. The molar mass of compound $(Y)$ is . . . . . . $\text{g mol}^{-1}$. (Nearest integer)
- A$26$
- B$28$
- C$30$
- D$32$
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$I$. $2 CH_3 Br \xrightarrow[\text{dry ether}]{Na}$
$II$. $CH_3 COOH \xrightarrow[CaO, \Delta]{NaOH}$
$III$. $CH_3 CH=CH_2 \xrightarrow{H_2 / Pt}$
$IV$. $CH_3 CH_2 Br \xrightarrow[H^{+}]{Zn}$
Correct answer is
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$Ph-CH_2-CH(CH_3)_2 \xrightarrow[hv]{Cl_2 (1 \ mol)}$ Major product
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