$A$ resistor is connected to a battery of $12 \text{ V}$ emf and internal resistance $2 \text{ }\Omega$. If the current in the circuit is $0.6 \text{ A}$, the terminal voltage of the battery is: (in $\text{ V}$)

  • A
    $12$
  • B
    $1.2$
  • C
    $10$
  • D
    $10.8$

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