$A$ particle of mass $m$ is executing $S.H.M.$ about the origin on the $x$-axis with frequency $f = \frac{\sqrt{Ka}}{\pi m}$, where $K$ is a constant and $a$ is the amplitude of $S.H.M.$ If $x$ is the displacement of the particle at time $t$, the potential energy of the particle will be:
- A$\frac{1}{2} K a x^2$
- B$\pi K a x^2$
- C$2 \pi K a x^2$
- D$2 K a x^2$
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