$A$ source of sound is moving towards a stationary observer with velocity $V_s$ and then moves away with velocity $V_s$. Assume that the medium through which the sound waves travel is at rest. If $V$ is the velocity of sound and $n$ is the frequency emitted by the source, then the difference between the apparent frequencies heard by the observer is:

  • A
    $\frac{2nV V_s}{V^2 - V_s^2}$
  • B
    $\frac{nV V_s}{V^2 - V_s^2}$
  • C
    $\frac{nV V_s}{V_s^2 + V^2}$
  • D
    $\frac{2nV V_s}{V_s^2 + V^2}$

Explore More

Similar Questions

$A$ source producing sound of frequency $170 \, Hz$ is approaching a stationary observer with a velocity $17 \, ms^{-1}$. The apparent change in the wavelength of sound heard by the observer is (speed of sound in air $= 340 \, ms^{-1}$) ..... $m$

With what velocity should an observer approach a stationary sound source,so that the apparent frequency of sound appears double the actual frequency? (Let $v$ be the velocity of sound).

An observer standing at a station observes a frequency of $219 \, Hz$ when a train approaches and $184 \, Hz$ when the train goes away from him. If the velocity of sound in air is $340 \, m/s$,then the velocity of the train and the actual frequency of the whistle will be:

Difficult
View Solution

An observer starts moving with uniform acceleration $a$ towards a stationary sound source of frequency $f$. As the observer approaches the source,the apparent frequency $f'$ heard by the observer varies with time $t$ as:

$A$ police car moving at $22 \ m/s$ chases a motorcyclist. The policeman sounds his horn at $176 \ Hz$,while both of them move towards a stationary siren of frequency $165 \ Hz$. Calculate the speed of the motorcycle,if it is given that he does not observe any beats. (in $m/s$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo