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(A) The fundamental frequency of wire $A$ is $f_A = 256 	ext{ Hz}$.The third harmonic of wire $A$ is $3 	imes f_A = 3 	imes 256 = 768 	ext{ Hz}$.T

Vedclass · Accepted Answer

$8$

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(A) The fundamental frequency of wire $A$ is $f_A = 256 	ext{ Hz}$.The third harmonic of wire $A$ is $3 	imes f_A = 3 	imes 256 = 768 	ext{ Hz}$.The fundamental frequency of wire $B$ is $f_B = 382 	ext{ Hz}$.The second harmonic of wire $B$ is $2 	imes f_B = 2 	imes 382 = 764 	ext{ Hz}$.The beat frequency is the absolute difference between the two frequencies: $|768 - 764| = 4 	ext{ Hz}$.This means $4$ beats are heard per second.Therefore, in $2$ seconds, the number of beats heard will be $4 	imes 2 = 8$.

$A$ and $B$ are two wires whose fundamental frequencies are $256 \text{ Hz}$ and $382 \text{ Hz}$ respectively. When the third harmonic of $A$ and the second harmonic of $B$ are sounded together, the number of beats heard in two seconds will be:

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