(A) The capacitance of a parallel plate capacitor with air is given by $C_0 = \frac{\epsilon_0 A}{d} = 15 \text{ pF}$.When the separation is doubled $

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(A) The capacitance of a parallel plate capacitor with air is given by $C_0 = \frac{\epsilon_0 A}{d} = 15 \text{ pF}$.When the separation is doubled $(d' = 2d)$ and a dielectric medium of constant $K = 3.5$ is introduced, the new capacitance $C'$ is given by $C' = \frac{K \epsilon_0 A}{d'}$.Substituting the values, $C' = \frac{3.5 \times \epsilon_0 A}{2d} = \frac{3.5}{2} \times C_0$.$C' = 1.75 \times 15 \text{ pF} = 26.25 \text{ pF}$.Given that $C' = x/4 \text{ pF}$, we have $26.25 = x/4$.Therefore, $x = 26.25 \times 4 = 105$.

Class 12 Physics Electric Potential and Capacitance Effect of Dielectric Inside Capacitor

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$A$ parallel plate capacitor with air between the plates has a capacitance of $15 \text{ pF}$. The separation between the plates is doubled and the space between them is filled with a medium of dielectric constant $3.5$. Then the capacitance becomes $x/4 \text{ pF}$. The value of $x$ is

MHT CET 2026 All MHT CET

A
$105$
B
$109$
C
$111$
D
$115$

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Class 12

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Electric Potential and Capacitance

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Effect of Dielectric Inside Capacitor

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$A$ parallel plate capacitor with air between the plates has a capacitance of $15 \text{ pF}$. The separation between the plates is doubled and the space between them is filled with a medium of dielectric constant $3.5$. Then the capacitance becomes $x/4 \text{ pF}$. The value of $x$ is

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