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Question

(C) The biconditional statement $p \Leftrightarrow q$ is defined as $(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow p)$.Since $p \Rightarrow q \equiv \si

Vedclass · Accepted Answer

$(p \wedge \sim q) \vee (\sim p \wedge q)$

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(C) The biconditional statement $p \Leftrightarrow q$ is defined as $(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow p)$.Since $p \Rightarrow q \equiv \sim p \vee q$,we have $p \Leftrightarrow q \equiv (\sim p \vee q) \wedge (\sim q \vee p)$.Taking the negation: $\sim (p \Leftrightarrow q) \equiv \sim ((\sim p \vee q) \wedge (\sim q \vee p))$.Using De Morgan's law: $\sim (p \Leftrightarrow q) \equiv \sim (\sim p \vee q) \vee \sim (\sim q \vee p)$.This simplifies to $(p \wedge \sim q) \vee (q \wedge \sim p)$.

$\sim (p \Leftrightarrow q)$ is

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