If overrightarrow A = 2hat i + hat j,overrigh | vedclass

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(B) Given vectors are $\overrightarrow A = 2\hat i + \hat j$,$\overrightarrow B = 3\hat j - \hat k$,and $\overrightarrow C = 6\hat i - 2\hat k$.We nee

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$20\hat i - 5\hat j - 4\hat k$

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(B) Given vectors are $\overrightarrow A = 2\hat i + \hat j$,$\overrightarrow B = 3\hat j - \hat k$,and $\overrightarrow C = 6\hat i - 2\hat k$.We need to calculate $\overrightarrow A - 2\overrightarrow B + 3\overrightarrow C$.Substituting the given vectors:$\overrightarrow A - 2\overrightarrow B + 3\overrightarrow C = (2\hat i + \hat j) - 2(3\hat j - \hat k) + 3(6\hat i - 2\hat k)$$= 2\hat i + \hat j - 6\hat j + 2\hat k + 18\hat i - 6\hat k$Grouping the components of $\hat i$,$\hat j$,and $\hat k$:$= (2 + 18)\hat i + (1 - 6)\hat j + (2 - 6)\hat k$$= 20\hat i - 5\hat j - 4\hat k$Thus,the correct option is $B$.

If $\overrightarrow A = 2\hat i + \hat j$,$\overrightarrow B = 3\hat j - \hat k$,and $\overrightarrow C = 6\hat i - 2\hat k$,then the value of $\overrightarrow A - 2\overrightarrow B + 3\overrightarrow C$ is:

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