Pascal-Second has the dimension of: | vedclass

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(D) The unit of pressure is $Pascal$ $(Pa)$,which has the dimensional formula $[M L^{-1} T^{-2}]$.Therefore,the dimensional formula of $Pascal-second$

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Coefficient of viscosity

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(D) The unit of pressure is $Pascal$ $(Pa)$,which has the dimensional formula $[M L^{-1} T^{-2}]$.Therefore,the dimensional formula of $Pascal-second$ $(Pa \cdot s)$ is $[M L^{-1} T^{-2}] 	imes [T] = [M L^{-1} T^{-1}]$.The coefficient of viscosity $(\eta)$ is defined by the formula:$\eta = \frac{F}{A (\Delta v / \Delta z)}$where $F$ is force,$A$ is area,and $\frac{\Delta v}{\Delta z}$ is the velocity gradient.The dimensions of $\eta$ are:$	ext{Dimensions of } \eta = \frac{[M L T^{-2}]}{[L^2] [T^{-1}]} = [M L^{-1} T^{-1}]$.Since the dimensions of $Pascal-second$ match the dimensions of the coefficient of viscosity,the correct option is $D$.

List $I$	List $II$
$A$. Torque	$I$. $[M^1 L^1 T^{-2} A^{-2}]$
$B$. Magnetic field	$II$. $[L^2 A^1]$
$C$. Magnetic moment	$III$. $[M^1 T^{-2} A^{-1}]$
$D$. Permeability of free space	$IV$. $[M^1 L^2 T^{-2}]$

$Pascal-Second$ has the dimension of:

Similar Questions

The pair of physical quantities not having the same dimensions is:

The pair having the same dimensions is

Match List $I$ with List $II$:

List $I$ List $II$

$A$. Torque $I$. $[M^1 L^1 T^{-2} A^{-2}]$

$B$. Magnetic field $II$. $[L^2 A^1]$

$C$. Magnetic moment $III$. $[M^1 T^{-2} A^{-1}]$

$D$. Permeability of free space $IV$. $[M^1 L^2 T^{-2}]$

Choose the correct answer from the options given below:

The phenomenon of physics that deals with the constitution and structure of matter at the minute scales of atoms and nuclei is

The graph between two quantities $P$ and $Q$ is a straight line passing through the origin when:

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