$16$ tuning forks are arranged in the order of increasing frequencies. Any two successive forks give $8$ beats per second when sounded together. If the frequency of the last fork is twice the first,then the frequency of the first fork is:

If two tuning forks $A$ and $B$ are sounded together,they produce $4$ beats per second. $A$ is then slightly loaded with wax,and they produce $2$ beats when sounded again. The frequency of $A$ is $256 \ Hz$. The frequency of $B$ will be: (in $Hz$)

$A$ tuning fork of unknown frequency produces $3 \, \text{beats/sec}$ with a standard tuning fork of frequency $384 \, \text{Hz}$. The beat frequency decreases when a small piece of wax is placed on the prong of the unknown tuning fork. The frequency of the unknown tuning fork is .... $\text{Hz}$

Two sound waves of wavelengths $5 \ m$ and $6 \ m$ produce $30$ beats in $3 \ s$. The velocity of sound is .... $m/s$.

The correct figure that shows,schematically,the wave pattern produced by the superposition of two waves of frequencies $9\,Hz$ and $11\,Hz$ is:

It is possible to hear beats from two vibrating sources of frequency: