How many molecules of water are required to c | vedclass

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(D) The Calvin cycle (also known as the $C_3$ cycle) is a light-independent reaction of photosynthesis.In the Calvin cycle,$3$ molecules of $CO_2$ are

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Six

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(D) The Calvin cycle (also known as the $C_3$ cycle) is a light-independent reaction of photosynthesis.In the Calvin cycle,$3$ molecules of $CO_2$ are fixed to produce one molecule of $Glyceraldehyde-3-phosphate$ $(G3P)$.To produce one molecule of glucose $(C_6H_{12}O_6)$,the cycle must turn $6$ times,fixing $6$ molecules of $CO_2$.Water $(H_2O)$ is primarily consumed during the light-dependent reactions (photolysis) to provide electrons,protons,and oxygen,not directly within the Calvin cycle itself.However,if the question refers to the stoichiometry of the overall photosynthetic equation $(6CO_2 + 12H_2O \rightarrow C_6H_{12}O_6 + 6O_2 + 6H_2O)$,the net consumption of water for the synthesis of one glucose molecule is $12$ molecules.Since the Calvin cycle is the dark reaction phase,it does not directly consume water molecules. However,in the context of standard textbook questions regarding the stoichiometry of the cycle's input for glucose synthesis,the answer is often considered $0$ for the cycle itself,but if the question implies the water required for the light reactions to support the fixation of $3$ $CO_2$ molecules (half a glucose),the answer is $6$ $H_2O$ molecules.

How many molecules of water are required to complete one Calvin cycle?

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