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(B) To determine the number of bases per codon,we use the formula $n^x \geq N$,where $n$ is the number of available bases,$x$ is the number of bases p

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$2$

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(B) To determine the number of bases per codon,we use the formula $n^x \geq N$,where $n$ is the number of available bases,$x$ is the number of bases per codon,and $N$ is the number of amino acids to be coded.Given $n = 12$ and $N = 96$.If $x = 1$,$12^1 = 12 If $x = 2$,$12^2 = 144$.Since $144 \geq 96$,the minimum number of bases required for each codon is $2$.

Suppose evolution on Earth occurred in such a way that instead of $20$ amino acids,there were $96$ amino acids. If $DNA$ consisted of $12$ different types of bases and $DNA$ synthesis occurred in the same manner,what would be the minimum number of bases required for each $DNA$ codon?

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