If there are 6 types of nitrogen bases and 40 | vedclass

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(A) Let $n$ be the number of nitrogen bases per codon and $b$ be the number of types of nitrogen bases available.Given $b = 6$ and the number of amino

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) Let $n$ be the number of nitrogen bases per codon and $b$ be the number of types of nitrogen bases available.Given $b = 6$ and the number of amino acids to be coded is $40$.The number of possible codons is given by $b^n$.We need to find the minimum integer $n$ such that $b^n \geq 40$.For $n = 1$: $6^1 = 6 For $n = 2$: $6^2 = 36 For $n = 3$: $6^3 = 216 \geq 40$.Therefore,the minimum number of nitrogen bases required to form a codon is $3$.

If there are $6$ types of nitrogen bases and $40$ types of amino acids available for protein synthesis,what is the minimum number of nitrogen bases required to form a codon in the genetic code?

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