(C) Potassium alum is $KAl(SO_4)_2 \cdot 12H_2O$. When $NaOH$ is added to it,initially $Al(OH)_3$ white precipitate is formed. $Al^{3+} + 3OH^- \right

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(C) Potassium alum is $KAl(SO_4)_2 \cdot 12H_2O$. When $NaOH$ is added to it,initially $Al(OH)_3$ white precipitate is formed. $Al^{3+} + 3OH^- \rightarrow Al(OH)_3 \downarrow$ On adding excess $NaOH$,the $Al(OH)_3$ precipitate dissolves to form a soluble complex,sodium tetrahydroxoaluminate$(III)$. $Al(OH)_3 + OH^- \rightarrow [Al(OH)_4]^-$ Thus,the final result is a clear solution.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

When an excess of $NaOH$ solution is added to a solution of potassium alum,what do we obtain?

A
White precipitate
B
Bluish white precipitate
C
Clear solution
D
Crystalline mass

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Level 0 of all question bank

The bleaching action of $SO_2$ is due to its .........

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Which of the following is a biodegradable pollutant?

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$S_1, S_2, \ldots, S_{10}$ are the speakers in a conference. If $S_1$ addresses only after $S_2$,then the number of ways the speakers address is

AP EAMCET 2004

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Match the List-$I$ with List-$II$:

List-$I$ (Isothermal process for ideal gas system) List-$II$ (Work done)

$(A)$ Reversible expansion $(I)$ $w = 0$

$(B)$ Free expansion $(II)$ $w = -nRT \ln \frac{V_f}{V_i}$

$(C)$ Irreversible expansion $(III)$ $w = -p_{ex}(V_f - V_i)$

$(D)$ Irreversible compression $(IV)$ $w = -p_{ex}(V_i - V_f)$

Choose the correct answer from the options given below:

List-$I$ (Isothermal process for ideal gas system)	List-$II$ (Work done)
$(A)$ Reversible expansion	$(I)$ $w = 0$
$(B)$ Free expansion	$(II)$ $w = -nRT \ln \frac{V_f}{V_i}$
$(C)$ Irreversible expansion	$(III)$ $w = -p_{ex}(V_f - V_i)$
$(D)$ Irreversible compression	$(IV)$ $w = -p_{ex}(V_i - V_f)$