Aqueous ammonia is used instead of an aqueous solution of $NaOH$ to precipitate $Al^{+3}$ ions as $Al(OH)_3$ because:

  • A
    $NH_4^+$ is a weak base.
  • B
    $NaOH$ forms $[Al(OH)_4]^-$ ions.
  • C
    $NaOH$ is a very strong base.
  • D
    $NaOH$ forms $[Al(OH)_4]^+$ ions.

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