Which of the following is the correct decreas | vedclass

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(A) The Lewis acid strength of boron halides is determined by the extent of $p\pi-p\pi$ back-bonding between the halogen atom and the boron atom. In $

Vedclass · Accepted Answer

$BBr_3 > BCl_3 > BF_3$

Vedclass · Answer

(A) The Lewis acid strength of boron halides is determined by the extent of $p\pi-p\pi$ back-bonding between the halogen atom and the boron atom. In $BF_3$,the small size of the fluorine atom allows for effective $2p-2p$ back-bonding with boron,which significantly reduces the electron deficiency of the boron atom. As the size of the halogen increases from $F$ to $Cl$ to $Br$,the effectiveness of back-bonding decreases ($2p-3p$ for $BCl_3$ and $2p-4p$ for $BBr_3$). Therefore,the electron deficiency on boron increases as we move from $BF_3$ to $BBr_3$,making $BBr_3$ the strongest Lewis acid and $BF_3$ the weakest. The correct decreasing order is $BBr_3 > BCl_3 > BF_3$.

Which of the following is the correct decreasing order of Lewis acid strength of boron halides?

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