In the hydrides of the nitrogen group,the H-M | vedclass

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(B) In the hydrides of group $15$ $(NH_3, PH_3, AsH_3, SbH_3, BiH_3)$,the central atom undergoes $sp^3$ hybridization in $NH_3$,leading to a bond angl

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Almost pure $p$-orbitals are used in $M-H$ bonds.

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(B) In the hydrides of group $15$ $(NH_3, PH_3, AsH_3, SbH_3, BiH_3)$,the central atom undergoes $sp^3$ hybridization in $NH_3$,leading to a bond angle of $107^o$. As we move down the group,the electronegativity of the central atom decreases. Consequently,the bond pairs of electrons move further away from the central atom and closer to the hydrogen atoms. This results in the central atom using almost pure $p$-orbitals for bonding,which have an inter-orbital angle of $90^o$. Therefore,the bond angle decreases from $107^o$ in $NH_3$ to nearly $90^o$ in $SbH_3$ and $BiH_3$.

In the hydrides of the nitrogen group,the $H-M-H$ bond angle gradually approaches $90^o$ as we move from $N$ to $Sb$. This indicates that gradually.....

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