X + H_2SO_4 to Y (a colorless gas with a pung | vedclass

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(A) $1$. The reaction $X + H_2SO_4 	o Y$ produces a colorless gas $Y$ with a pungent smell. This is characteristic of $SO_2$ gas,which is evolved fro

Vedclass · Accepted Answer

$SO_3^{2-}, SO_2$

Vedclass · Answer

(A) $1$. The reaction $X + H_2SO_4 	o Y$ produces a colorless gas $Y$ with a pungent smell. This is characteristic of $SO_2$ gas,which is evolved from sulfites $(SO_3^{2-})$.$2$. $SO_2$ acts as a reducing agent. When passed through an acidified potassium dichromate solution $(K_2Cr_2O_7 + H_2SO_4)$,it reduces $Cr(VI)$ to $Cr(III)$,which is green in color.$3$. The reaction is: $K_2Cr_2O_7 + H_2SO_4 + 3SO_2 	o K_2SO_4 + Cr_2(SO_4)_3 + H_2O$.$4$. Thus,$X$ is $SO_3^{2-}$ and $Y$ is $SO_2$.

$X + H_2SO_4 \to Y$ (a colorless gas with a pungent smell).
$Y + K_2Cr_2O_7 + H_2SO_4 \to$ green colored solution.
What are $X$ and $Y$?

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$X + H_2SO_4 \to Y$ (a colorless gas with a pungent smell).$Y + K_2Cr_2O_7 + H_2SO_4 \to$ green colored solution.What are $X$ and $Y$?