(C) The formula for the number of different genotypes produced by a self-cross of an organism with $n$ heterozygous gene pairs is $3^n$.In the given g

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(C) The formula for the number of different genotypes produced by a self-cross of an organism with $n$ heterozygous gene pairs is $3^n$.In the given genotype $AaBbCcDdEeFfGg$,we count the number of heterozygous pairs $(n)$:$Aa$ $(1)$,$Bb$ $(2)$,$Cc$ $(3)$,$Dd$ $(4)$,$Ee$ $(5)$,$Ff$ $(6)$,$Gg$ $(7)$.Thus,$n = 7$.The number of different genotypes is $3^n = 3^7$.

Class 12 Biology Principles of Inheritance and Variation Inheritance of one gene

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If $3^n$ is the theoretical number of different genotypes (where $n$ is the number of heterozygous gene pairs),then the number of different genotypes produced by a pea plant with the genotype $AaBbCcDdEeFfGg$ is:

A
$3^{10}$
B
$3^{12}$
C
$3^7$
D
$3^{14}$

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Principles of Inheritance and Variation

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Inheritance of one gene

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If $3^n$ is the theoretical number of different genotypes (where $n$ is the number of heterozygous gene pairs),then the number of different genotypes produced by a pea plant with the genotype $AaBbCcDdEeFfGg$ is:

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